2(2x+3)=2[3(3x-4)+8]

Solution for 2(2x+3)=2[3(3x-4)+8] equation:

Simplifying
2(2x + 3) = 2[3(3x + -4) + 8]

Reorder the terms:
2(3 + 2x) = 2[3(3x + -4) + 8]
(3 * 2 + 2x * 2) = 2[3(3x + -4) + 8]
(6 + 4x) = 2[3(3x + -4) + 8]

Reorder the terms:
6 + 4x = 2[3(-4 + 3x) + 8]
6 + 4x = 2[(-4 * 3 + 3x * 3) + 8]
6 + 4x = 2[(-12 + 9x) + 8]

Reorder the terms:
6 + 4x = 2[-12 + 8 + 9x]

Combine like terms: -12 + 8 = -4
6 + 4x = 2[-4 + 9x]
6 + 4x = [-4 * 2 + 9x * 2]
6 + 4x = [-8 + 18x]

Solving
6 + 4x = -8 + 18x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-18x' to each side of the equation.
6 + 4x + -18x = -8 + 18x + -18x

Combine like terms: 4x + -18x = -14x
6 + -14x = -8 + 18x + -18x

Combine like terms: 18x + -18x = 0
6 + -14x = -8 + 0
6 + -14x = -8

Add '-6' to each side of the equation.
6 + -6 + -14x = -8 + -6

Combine like terms: 6 + -6 = 0
0 + -14x = -8 + -6
-14x = -8 + -6

Combine like terms: -8 + -6 = -14
-14x = -14

Divide each side by '-14'.
x = 1

Simplifying
x = 1